F(x)= x^4-4mx²+2, find m, so that f(x) has three max/min points which form?

a triangle whose barycenter is at the origin?
so y'= 4x³-8mx =0,
x=0, or x=± √(2m)
let A(0,2, B(√(2m), f(√(2m)) and C( -√(2m), f(-√(2m))
How do I locate the barycenter which satisfies the question? thanks for helping.
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